NaReO4 + Na[BH4] + HCl = ReO2 + H3BO3 + NaCl + H2O |

8NaReO₄ + 3Na[BH₄] + 11HCl → 8ReO₂ + 3H₃BO₃ + 11NaCl + 7H₂O

Sodium perrhenate react with sodium tetrahydroxoborate(III) and hydrogen chloride to produce rhenium(IV) oxide, orthoboric acid, hydrogen chloride and water. This reaction takes place in the medium of ester.

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Sodium perrhenate react with sodium tetrahydroxoborate(III) and hydrogen chloride

8NaReO₄ + 3Na[BH₄] + 11HCl → 8ReO₂ + 3H₃BO₃ + 11NaCl + 7H₂O

Picture of reaction:

Сoding to search: 8 NaReO4 + 3 NaBH4 + 11 HCl = 8 ReO2 + 3 H3BO3 + 11 NaCl + 7 H2O

Add / Edited: 26.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Sodium perrhenate react with sodium tetrahydroxoborate(III) and hydrogen chloride

8NaReO4 + 3Na[BH4] + 11HCl → 8ReO2 + 3H3BO3 + 11NaCl + 7H2O

Picture of reaction:

Сoding to search: 8 NaReO4 + 3 NaBH4 + 11 HCl = 8 ReO2 + 3 H3BO3 + 11 NaCl + 7 H2O

Add / Edited: 26.06.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

8NaReO₄ + 3Na[BH₄] + 11HCl → 8ReO₂ + 3H₃BO₃ + 11NaCl + 7H₂O

Add / Edited: 26.06.2015 /