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Lead(II) chloride react with potassium iodide

PbCl2 + 2KI → PbI2 + 2KCl

Lead(II) chloride react with potassium iodide to produce lead(II) iodide and potassium chloride. Potassium iodide - diluted solution.

Picture of reaction: img1 BB html

Сoding to search: PbCl2 + 2 KI = PbI2 + 2 KCl

Add / Edited: 03.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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