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The decomposition of sodium triiodoplumbate(II)
Na[PbI
3
] → NaI + PbI
2
[ Check the balance ]
The decomposition of sodium triiodoplumbate(II) to produce sodium iodide and lead(II) iodide. This reaction takes place by diluting the solution sodium triiodoplumbate(II).
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Picture of reaction:
Сoding to search:
NaPbI3 = NaI + PbI2
Add / Edited:
04.07.2015 /
Evaluation of information:
5.0 out of 5 / number of votes: 1
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