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Lead(II) oxide react with sodium hydroxide

PbO + 2NaOH → Na2PbO2 + H2O

Lead(II) oxide react with sodium hydroxide to produce lead(II)-sodium oxide and water. This reaction takes place at a temperature near 400°C.

Picture of reaction: img1 BB html

Сoding to search: PbO + 2 NaOH cnd [ temp ] = Na2PbO2 + H2O

Add / Edited: 04.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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