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Lead(II) sulfide react with chlorine

2PbS + 3Cl2 → 2PbCl2 + S2Cl2

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Lead(II) sulfide react with chlorine to produce lead(II) chloride and disulfur dichloride. This reaction takes place at a temperature of 100-150°C. Impurities: chloride sulfur(II) SCl2.

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Сoding to search: 2 PbS + 3 Cl2 cnd [ temp ] = 2 PbCl2 + S2Cl2

Add / Edited: 04.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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