PdCl2 + HCl + HNO3 = H2[PdCl6] + NO + H2O |

3PdCl₂ + 12HCl + 2HNO₃ → 3H₂[PdCl₆] + 2NO + 4H₂O

Palladium(II) chloride react with hydrogen chloride and nitric acid to produce hydrogen hexachloridopalladate(IV), nitric oxide and water. Hydrogen chloride and nitric acid - concentrated solutions.

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Palladium(II) chloride react with hydrogen chloride and nitric acid

3PdCl₂ + 12HCl + 2HNO₃ → 3H₂[PdCl₆] + 2NO + 4H₂O

Picture of reaction:

Сoding to search: 3 PdCl2 + 12 HCl + 2 HNO3 = 3 H2PdCl6 + 2 NO + 4 H2O

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Palladium(II) chloride react with hydrogen chloride and nitric acid

3PdCl2 + 12HCl + 2HNO3 → 3H2[PdCl6] + 2NO + 4H2O

Picture of reaction:

Сoding to search: 3 PdCl2 + 12 HCl + 2 HNO3 = 3 H2PdCl6 + 2 NO + 4 H2O

Add / Edited: 05.07.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

3PdCl₂ + 12HCl + 2HNO₃ → 3H₂[PdCl₆] + 2NO + 4H₂O

Add / Edited: 05.07.2015 /