Home Reactions Blog
Language: ru es en
Chemiday Log in:

The thermal decomposition of ammonium hexachloridopalladate(IV)

3(NH4)2[PdCl6] → 3Pd + 2N2 + 2NH4Cl + 16HCl


The thermal decomposition of ammonium hexachloridopalladate(IV) to produce palladium, nitrogen, ammonium chloride and hydrogen chloride. This reaction takes place at a temperature near 500°C.


Picture of reaction: img1 BB html

Сoding to search: 3 NH42PdCl6 cnd [ temp ] = 3 Pd + 2 N2 + 2 NH4Cl + 16 HCl

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


Please register to post comments
ChemiDay you always could choose go nuts or keep calm with us or without.
About | Feedback and suggestions | Contact us | Author
Хостинг от uWebChemiDay.com © 2024
Cookies policy, User agreement, Privacy policy.