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Palladium(II) chloride react with potassium iodide

PdCl2 + 2KI → PdI2 + 2KCl


Palladium(II) chloride react with potassium iodide to produce palladium(II) iodide and potassium chloride. Impurities: tetraiodopaladate(II) potassium K2[PdCl4].


Picture of reaction: img1 BB html

Сoding to search: PdCl2 + 2 KI = PdI2 + 2 KCl

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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