PdCl2 + HBr = H2[PdBr4] + HCl |

PdCl₂ + 4HBr → H₂[PdBr₄] + 2HCl

Palladium(II) chloride react with hydrogen bromide to produce hydrogen tetrabromidopalladate(II) and hydrogen chloride. Hydrogen bromide - concentrated solution.

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Palladium(II) chloride react with hydrogen bromide

PdCl₂ + 4HBr → H₂[PdBr₄] + 2HCl

Picture of reaction:

Сoding to search: PdCl2 + 4 HBr = H2PdBr4 + 2 HCl

Add / Edited: 05.07.2015 /

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Palladium(II) chloride react with hydrogen bromide

PdCl2 + 4HBr → H2[PdBr4] + 2HCl

Picture of reaction:

Сoding to search: PdCl2 + 4 HBr = H2PdBr4 + 2 HCl

Add / Edited: 05.07.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

PdCl₂ + 4HBr → H₂[PdBr₄] + 2HCl

Add / Edited: 05.07.2015 /