PdCl2 + KCN = K2[Pd(CN)4] + KCl |

PdCl₂ + 4KCN K₂[Pd(CN)₄] + 2KCl

Palladium(II) chloride react with potassium cyanide to produce potassium tetracyanopalladate(II) and potassium chloride. Potassium cyanide - concentrated solution. This reaction takes place at a temperature of 60-80°C.

Find another reaction

Thermodynamic properties of substances

The solubility of the substances

Periodic table of elements

Palladium(II) chloride react with potassium cyanide

PdCl₂ + 4KCN K₂[Pd(CN)₄] + 2KCl

Picture of reaction:

Сoding to search: PdCl2 + 4 KCN cnd [ temp ] = K2PdCN4 + 2 KCl

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Palladium(II) chloride react with potassium cyanide

PdCl2 + 4KCN K2[Pd(CN)4] + 2KCl

Picture of reaction:

Сoding to search: PdCl2 + 4 KCN cnd [ temp ] = K2PdCN4 + 2 KCl

Add / Edited: 05.07.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

PdCl₂ + 4KCN K₂[Pd(CN)₄] + 2KCl

Add / Edited: 05.07.2015 /