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Palladium(II) cyanide react with potassium cyanide and potassium

Pd(CN)2 + 2KCN + 2K → K4[Pd(CN)4]


Palladium(II) cyanide react with potassium cyanide and potassium to produce potassium tetracyanopalladate(0). The reaction is conducted in a liquid ammonia, at a temperature near -50°C.


Picture of reaction: img1 BB html

Сoding to search: PdCN2 + 2 KCN + 2 K = K4PdCN4

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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