K2[PdCl6] + Hg(CN)2 = Pd(CN)4 + HgCl2 + KCl |

K₂[PdCl₆] + 2Hg(CN)₂ → Pd(CN)₄ + 2HgCl₂ + 2KCl

Potassium exachloridopalladate(IV) react with mercury(II) cyanide to produce palladium(IV) cyanide, mercury(II) chloride and potassium chloride. This reaction takes place at a temperature near 10°C in the diluted solution hydrogen chloride.

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Potassium exachloridopalladate(IV) react with mercury(II) cyanide

K₂[PdCl₆] + 2Hg(CN)₂ → Pd(CN)₄ + 2HgCl₂ + 2KCl

Picture of reaction:

Сoding to search: K2PdCl6 + 2 HgCN2 = PdCN4 + 2 HgCl2 + 2 KCl

Add / Edited: 05.07.2015 /

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Potassium exachloridopalladate(IV) react with mercury(II) cyanide

K2[PdCl6] + 2Hg(CN)2 → Pd(CN)4 + 2HgCl2 + 2KCl

Picture of reaction:

Сoding to search: K2PdCl6 + 2 HgCN2 = PdCN4 + 2 HgCl2 + 2 KCl

Add / Edited: 05.07.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

K₂[PdCl₆] + 2Hg(CN)₂ → Pd(CN)₄ + 2HgCl₂ + 2KCl

Add / Edited: 05.07.2015 /