PdF3 + HCl = H2[PdCl4] + HF + Cl2 |

2PdF₃ + 10HCl → 2H₂[PdCl₄] + 6HF + Cl₂

Palladium(III) fluoride react with hydrogen chloride to produce hydrogen tetrachloridopalladate(II), hydrogen fluoride and chlorine. Hydrogen chloride - concentrated solution.

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Palladium(III) fluoride react with hydrogen chloride

2PdF₃ + 10HCl → 2H₂[PdCl₄] + 6HF + Cl₂

Picture of reaction:

Сoding to search: 2 PdF3 + 10 HCl = 2 H2PdCl4 + 6 HF + Cl2

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Palladium(III) fluoride react with hydrogen chloride

2PdF3 + 10HCl → 2H2[PdCl4] + 6HF + Cl2

Picture of reaction:

Сoding to search: 2 PdF3 + 10 HCl = 2 H2PdCl4 + 6 HF + Cl2

Add / Edited: 05.07.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

2PdF₃ + 10HCl → 2H₂[PdCl₄] + 6HF + Cl₂

Add / Edited: 05.07.2015 /