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Palladium(III) fluoride react with hydrogen chloride and nitric acid

3PdF3 + 18HCl + HNO3 → 3H2[PdCl6] + NO + 9HF + 2H2O


Palladium(III) fluoride react with hydrogen chloride and nitric acid to produce hydrogen hexachloridopalladate(IV), nitric oxide, hydrogen fluoride and water. Hydrogen chloride and nitric acid - concentrated solutions.


Picture of reaction: img1 BB html

Сoding to search: 3 PdF3 + 18 HCl + HNO3 = 3 H2PdCl6 + NO + 9 HF + 2 H2O

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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