PdF3 + NaOH = Pd(OH)2 + O2 + NaF + H2O |

4PdF₃ + 12NaOH → 4Pd(OH)₂ + O₂ + 12NaF + 2H₂O

Palladium(III) fluoride react with sodium hydroxide to produce palladium(II) hydroxide, oxygen, sodium fluoride and water. Sodium hydroxide - diluted solution.

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Palladium(III) fluoride react with sodium hydroxide

4PdF₃ + 12NaOH → 4Pd(OH)₂ + O₂ + 12NaF + 2H₂O

Picture of reaction:

Сoding to search: 4 PdF3 + 12 NaOH = 4 PdOH2 + O2 + 12 NaF + 2 H2O

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Palladium(III) fluoride react with sodium hydroxide

4PdF3 + 12NaOH → 4Pd(OH)2 + O2 + 12NaF + 2H2O

Picture of reaction:

Сoding to search: 4 PdF3 + 12 NaOH = 4 PdOH2 + O2 + 12 NaF + 2 H2O

Add / Edited: 05.07.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

4PdF₃ + 12NaOH → 4Pd(OH)₂ + O₂ + 12NaF + 2H₂O

Add / Edited: 05.07.2015 /