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Palladium(III) fluoride react with sulfur dioxide

2PdF3 + SO2 → 2PdF2 + SO2F2


Palladium(III) fluoride react with sulfur dioxide to produce palladium(II) fluoride and sulfur(VI) difluoride-dioxide. This reaction takes place at a temperature near 200°C.


Picture of reaction: img1 BB html

Сoding to search: 2 PdF3 + SO2 cnd [ temp ] = 2 PdF2 + SO2F2

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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