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Palladium(III) fluoride react with sulfur tetrafluoride

2PdF3 + SF4 → 2PdF2 + SF6

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Palladium(III) fluoride react with sulfur tetrafluoride to produce palladium(II) fluoride and sulfur hexafluoride. This reaction takes place at a temperature near 200°C.

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Сoding to search: 2 PdF3 + SF4 cnd [ temp ] = 2 PdF2 + SF6

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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