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Palladium(III) fluoride react with xenon difluoride

2PdF3 + 2XeF2 → (XeF)[Pd2F9] + Xe


Palladium(III) fluoride react with xenon difluoride to produce fluoroxenon(II) nonafluorodipalladate(IV) and xenon. The reaction is conducted in a liquid hydrogen fluoride.


Picture of reaction: img1 BB html

Сoding to search: 2 PdF3 + 2 XeF2 = XeFPd2F9 + Xe

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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