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The thermal decomposition of dichlorodiamminepalladium(II)

3[Pd(NH3)2Cl2] → 3Pd + 4NH4Cl + 2HCl + N2

The thermal decomposition of dichlorodiamminepalladium(II) to produce palladium, ammonium chloride, hydrogen chloride and nitrogen. This reaction takes place at a temperature of over 210°C.

Picture of reaction: img1 BB html

Сoding to search: 3 PdNH32Cl2 cnd [ temp ] = 3 Pd + 4 NH4Cl + 2 HCl + N2

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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