Home Reactions Blog
Language: ru es en
Chemiday Log in:

The thermal decomposition of dichlorodiamminepalladium(II)

3[Pd(NH3)2Cl2] → 3Pd + 4NH4Cl + 2HCl + N2

[ Check the balance ]
The thermal decomposition of dichlorodiamminepalladium(II) to produce palladium, ammonium chloride, hydrogen chloride and nitrogen. This reaction takes place at a temperature of over 210°C.

poiskFind another reaction
Thermodynamic properties Thermodynamic properties of substances
Table of solubility The solubility of the substances
Periodic Table Periodic table of elements

Picture of reaction: img1 BB html

Сoding to search: 3 PdNH32Cl2 cnd [ temp ] = 3 Pd + 4 NH4Cl + 2 HCl + N2

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Please register to post comments
ChemiDay you always could choose go nuts or keep calm with us or without.
About | Feedback and suggestions | Contact us | Author
Хостинг от uWebChemiDay.com © 2024
Cookies policy, User agreement, Privacy policy.