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Dichloridodiamminepalladium(II) react with sodium hydroxide

[Pd(NH3)2Cl2] + 2NaOH → Pd(OH)2 + 2NaCl + 2NH3


Dichloridodiamminepalladium(II) react with sodium hydroxide to produce palladium(II) hydroxide, sodium chloride and ammonia. Sodium hydroxide diluted solution. The reaction takes place in a boiling solution.


Picture of reaction: img1 BB html

Сoding to search: PdNH32Cl2 + 2 NaOH cnd [ temp ] = PdOH2 + 2 NaCl + 2 NH3

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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