Home Reactions Blog
Language: ru es en
Chemiday Log in:

Dichloridodiamminepalladium(II) react with hydrogen

[Pd(NH3)2Cl2] + H2 → Pd + 2NH4Cl


Dichloridodiamminepalladium(II) react with hydrogen to produce palladium and ammonium chloride. This reaction takes place at a temperature near 900°C.


Picture of reaction: img1 BB html

Сoding to search: PdNH32Cl2 + H2 cnd [ temp ] = Pd + 2 NH4Cl

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


Please register to post comments
ChemiDay you always could choose go nuts or keep calm with us or without.
About | Feedback and suggestions | Contact us | Author
Хостинг от uWebChemiDay.com © 2024
Cookies policy, User agreement, Privacy policy.