[Pd(NH3)2Cl4] + NaOH = PdO2 + NH3 + NaCl + H2O |

[Pd(NH₃)₂Cl₄] + 4NaOH PdO₂ + 2NH₃ + 4NaCl + 2H₂O

Tetrachloridodiamminepalladium(IV) react with sodium hydroxide to produce palladium(IV) oxide, ammonia, sodium chloride and water. Sodium hydroxide - diluted solution. The reaction takes place in a boiling solution.

Find another reaction

Thermodynamic properties of substances

The solubility of the substances

Periodic table of elements

Tetrachloridodiamminepalladium(IV) react with sodium hydroxide

[Pd(NH₃)₂Cl₄] + 4NaOH PdO₂ + 2NH₃ + 4NaCl + 2H₂O

Picture of reaction:

Сoding to search: PdNH32Cl4 + 4 NaOH cnd [ temp ] = PdO2 + 2 NH3 + 4 NaCl + 2 H2O

Add / Edited: 05.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Tetrachloridodiamminepalladium(IV) react with sodium hydroxide

[Pd(NH3)2Cl4] + 4NaOH PdO2 + 2NH3 + 4NaCl + 2H2O

Picture of reaction:

Сoding to search: PdNH32Cl4 + 4 NaOH cnd [ temp ] = PdO2 + 2 NH3 + 4 NaCl + 2 H2O

Add / Edited: 05.07.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

[Pd(NH₃)₂Cl₄] + 4NaOH PdO₂ + 2NH₃ + 4NaCl + 2H₂O

Add / Edited: 05.07.2015 /